This Blog exists for the collective benefit of all geometry students. While the posts are specific to Mr. Chamberlain's class, any and all "geometricians" are welcome. The more specific your question (including your own attempts to answer it) the better.
oops... by the way, can you explain the proof on the chapter 6 test. even after 5 times. i can't get it.
ReplyDeleteBasically,
ReplyDeleteAB cong. BC | Given
tri-ABC is isosceles | Def'n Isos
angl-B cong. angl-ACB | Isos Trngl Thm
angl-ACB is an exterior angle to tri-ADC | Defn
angl-ACB > angl-D | Ext angle inequality
angl-B > angl-D | Substitution